ax^4+bx^2+x+5, f(-3)=2, f(3)= ?

• given
  f(-3)=2, it is possible when -3+5=2
  f(3)=3+5=8
• 11 years agoHelpfull: Yes(11) No(1)
• since x^4 and x^2 remains same the only change in x now if (-3) is 2.
  the value of ax^4+bx^2+5 is 5 so, f(3) is 5+3=8. which is the required answer.
• 11 years agoHelpfull: Yes(1) No(0)
• the answer is 10.
  
• 11 years agoHelpfull: Yes(0) No(0)
• sorry i made a mistake...the answer should be 8.
• 11 years agoHelpfull: Yes(0) No(0)