A series of books were published at seven years intervals when the seventh book was issued the sum of the

the answer below is incorrect.the calculation gives answer as 1911
x+x+7+x+14+x+21+x+28+x+35+x+42=13524
7x+147=13524 then x=1911
10 years agoHelpfull: Yes(18) No(0)

avg of 7 books= 13524/7= 1932

1932-3(7)=1911 (7+7+7)=for 3times before 4th book was published
10 years agoHelpfull: Yes(4) No(1)
Let x be the 1st book published year
so yrs : x,x+7,x+14,x+21,x+28,x+35,x+42
sum=13524
x+x+7+x+14+x+21+x+28+x+35+x+42=13524
7x+147=a3524 => 7x=13377
x=1900
10 years agoHelpfull: Yes(4) No(7)
let x be the year it was published for the first time,
then
x+(x+7)+(x+14)+.....+(x+42)= 13524(this series on left is in A.P and it is for 7 editions as given)
therefore, x=1911
10 years agoHelpfull: Yes(2) No(0)
sorry it is 1911
10 years agoHelpfull: Yes(2) No(1)
a.1911
13524=3.5*(2*a)+42
10 years agoHelpfull: Yes(2) No(0)
a) 1911
let x be the first year and add +7 each year till 7th book as their sum is equal to 13524. So,
x + x+7 + x+14 + x+21 + x+28 + x+35 + x+42 =13524
solve it you get x = 1911
6 years agoHelpfull: Yes(0) No(0)

A series of books were published at seven years intervals when the seventh book was issued the sum of the publications years was 13524, when the first book was published?
a) 1911
b) 1800
c) 1900
d) 1811