One day Esta started 30 min late from home and reached the office 50 min late while driving 25% slower than her usual speed. How much time in minutes does Esta take to reach her office from home?
a) 40
b) 60
c) 80
d) 20

• as he started 30 mins late and reached 50 min late the diff in time =(50-30)=20 min
  let x=speed,t=time
  xt=distance
  xt=(3/4)(x)(t+20)
  by solving we get t=60 min
  total time taken to reach her office is 60 min
• 11 years agoHelpfull: Yes(24) No(1)
• Difference in time = 50-30=20mins
  New speed = 100-25/100=75/100=3/4 of usual speed
  New time = 4/3 of usual time
  New time - Usual time=20
  4/3 of usual time - usual time=20
  So Time taken to reach her office is 60mins
  
• 11 years agoHelpfull: Yes(19) No(1)
• even though she was delayed but the distance from office to home is same,
  so let x be the speed and t be the time initially and due to delay the new speed was x-x/4=3x/4 and new time is t+20(since 20 min delay),so
  initial distance = x*t
  and new distance = (3x/4)*(t+20),
  and as i said distance are equal
  so, x*t = (3x/4)*(t+20)
  => t=60 min
• 11 years agoHelpfull: Yes(5) No(1)