If A^B means A raised to the power of B, in which of the following choices must P be greater than Q
a) 0.9^P=0.9^Q
b) 0.9^P=0.92^Q
c) 0.9^P>0.9^q

• d) none of these
• 11 years agoHelpfull: Yes(23) No(4)
• B
  A for A to be true p must be equal to Q
  and for C to be true Q must be greater than p
  which leaves C
• 11 years agoHelpfull: Yes(20) No(17)
• B IS NOT TRUE..TAKING LOG WE HAVE P LOG 0.9=Q LOG 0.92..
  SO, P/Q = LOG 0.92/LOG 0.9 =0.79
  SO,P HAS TO B LESS THAN Q THERWISE P/Q WUD B MORE THAN 1.
  HENCE..OPTN B IS WRONG..
  OPTN A IS OBVIUSLY WRONG..
  CORRECT 1 IS OPTN C..I THINK SO
• 11 years agoHelpfull: Yes(9) No(5)
• ans is b (0.9)^p=(0.92)^q
  because all other optn not satisfied the cond
• 11 years agoHelpfull: Yes(5) No(4)
• c in these 0.9 should be commn
• 11 years agoHelpfull: Yes(5) No(4)
• hahaha.. LOL.. c c c
• 11 years agoHelpfull: Yes(2) No(10)
• First of all its not a 'LOL' question..lets take an example (.9)2 =.81 (.9)3 =.73
  (.9)2 > (.9)3 p=2 q=3 p
• 11 years agoHelpfull: Yes(2) No(0)
• a)0.9^p=0.9^q,therefore p=Q
  b)
  taking log on both side,
  plog(0.9)=Qlog(0.92)
  p/Q=log(0.92)/log(0.9)
  p/Q>1
  i.e,p>Q
• 11 years agoHelpfull: Yes(2) No(4)
• to satisfy the condition of option c p should be less then q.
  b is the right
• 11 years agoHelpfull: Yes(1) No(3)
• option d is missing dude
  
• 11 years agoHelpfull: Yes(1) No(3)
• Option A is wrong as P = Q
  Option B is wrong as P/Q=Log0.92/Log0.9=0.79139
  Option C is also wrong as aP>aQ then P>Q if a > 1
• 9 years agoHelpfull: Yes(1) No(1)
• guys answer is 0.9P>0.9Q which is noT given in the options
• 8 years agoHelpfull: Yes(1) No(0)
• none of these
  the correct answer is 0.9P>0.9Q
• 7 years agoHelpfull: Yes(1) No(0)
• option d.
  
  when we are calculate one decimal value with powers then value will be reduced.so
  option a,b,c false.
  9*2>9*1=18>9 because p must be greater than.
• 11 years agoHelpfull: Yes(0) No(1)
• please explain clearly
  
• 9 years agoHelpfull: Yes(0) No(0)
• Option c
  Take log on both side,
  P log0.9 > q log 0.9
  P > q (log 0.9/log 0.9)
  P>q.
  This satisfies the condition
• 8 years agoHelpfull: Yes(0) No(0)