summation from i=0 to 6409 of ai=? where:
ai= 29(if ai is divided by 13 & 17)
ai= 17(if ai is divided by 13 & 29)
ai= 13(if ai is divided by 17 & 29)
ai=0(else)

• divided by 13 & 17 then:-
  221(1,2,3,.............,29)
  so, total no is 29 then sum=29*29=841
  divided by 13 & 29 then :-
  377(1,2,3,..............,17)
  so, total no is 17 then sum=17*17=289
  divided by 17 & 29 then:-
  493(1,2,3,..............,13)
  so, total no is 13 then sum=13*13=169
  
  
  so, total sum=841+289+169=1299
• 11 years agoHelpfull: Yes(2) No(1)
• For 6409 it is 6409=29*13*17
  For 1 less than 6409 i.e. 6408=(29*28)+(13*12)+(17*16)=1240 ANS.
• 8 years agoHelpfull: Yes(1) No(0)