Two full tanks one shaped like the cylinder and the other like a cone contain liquid fuel the cylindrical tank held 500 lts more then the conolical tank After 200 lts of fuel is pumped out from each tank the cylindrical tank now contains twice the amount of fuel in the canonical tank How many lts of fuel did the cylindrical tank have when it was full?

• let area of cylinder=A
  & area of cone=B
  acc. to ques,
  A=B+500 .....(1)
  A-200=2(B-200) .....(2)
  from (1) &(2)
  A=1200
  volume of fuel when cylinder is full=1200 lts
  
• 11 years agoHelpfull: Yes(61) No(2)
• consider the colonical tank contains x lts
  cylindrical tank then contains x+500 lts
  after pumping of 200 lts from each tank..... now the tanks cntain x-200 lts & x+300 lts
  x+300=2(x-200)
  x=700 lts
  originally cylindrical tank contains x+500 lts
  therefore ans is 700+500= 1200 lts
• 11 years agoHelpfull: Yes(25) No(0)
• let the amount of fuel present in conical tank=x
  then fuel in cylindrical tank is=500+x
  200 lit of fuel was pumped out of each tank then
  remaining is
  (300+x)=2(x-200)
  x=700
  total amount of fuel in cylindrical tank=(500+700)=1200lit
• 11 years agoHelpfull: Yes(6) No(0)
• x+300=2(x-200)
  x=700lts
  already there is 500 lts
  therefore x+500=700+500=1200lts
  
• 10 years agoHelpfull: Yes(2) No(0)
• Let the cylindrical tank capacity x + 500 then the conical tank capacity = x
  After 200 lts pumped out, then remaining fuel with the tanks = x +300, x - 200
  Given that first term is doubt the second.
  x
  +
  300
  x
  −
  200
  =
  2
  1
  x+300x−200=21
  Solving we get x = 700
  Cylindrical tank capacity = 1200 lts
• 6 years agoHelpfull: Yes(0) No(0)