If 5+3+2=151022, 9+2+4=183652, then 7+2+5=?

• the first and second digits are the product of a and b =>5*3=15
  the third and fourth digits are the product of a and c =>5*2=10
  let 15=x & 10=y
  fifth and sixth term = (x+y)-b =>(15+10)-3=22
  similarly:for 7+2+5,
  1st and 2nd term:=7*2=14
  3rd and 4th term:=7*5=35
  5th and 6th term:=(14+35)-2=47
  therefore 7+2+5=143547
  
• 11 years agoHelpfull: Yes(40) No(0)
• a+b+c = a*b | a*c | [a*b+a*c]-b
  7+2+5 = 7*2 | 7*5 | [14+35]-2 = 143547
• 11 years agoHelpfull: Yes(9) No(1)
• 5+3+2=(5*3)(5*2)(5*3+5*2-3)
  9+2+4=(9*2)(9*4)(9*2+9*4-2)
  7+2+5=(7*2)(7*5)(7*2+7*5-2)=143547
• 11 years agoHelpfull: Yes(4) No(1)
• 5+3+2=151022
  ans:-
  1)a*b=5*3=15
  2)a*c=5*2=10
  3)(a*b+b*c)-b=(15+10)-3=22
  =151022
  so...
  7+2+5=?
  ANS:-
  A*B=14
  A*C=35
  (A*B+A*C)-B=(14+35)-2=47
  =143547 THIS IS THE ANS FOR THIS QUESTION.
• 11 years agoHelpfull: Yes(1) No(0)
• 7+2+5= 143555
  7*2=14
  7*5=35
  7+2+2=11*5=55
• 11 years agoHelpfull: Yes(0) No(3)
• 7+2+5=143553
• 11 years agoHelpfull: Yes(0) No(3)
• 7+2+5=(7*2)(7*5)(14+35-2)=143547
• 11 years agoHelpfull: Yes(0) No(1)
• 7+2+5=(7*2)(7*5)(7*2+7*5-2)=143547
• 11 years agoHelpfull: Yes(0) No(1)
• 7*2+7*5=49-2=47
  ans:)143547
• 11 years agoHelpfull: Yes(0) No(2)
• according to, (5*3)(5*2)(15+10-3)..=151022
  SO..7+2+5 = 143547
• 11 years agoHelpfull: Yes(0) No(1)
• 7+2+5=(7*2)(7*5)(7*2+7*5-2)=143547
• 11 years agoHelpfull: Yes(0) No(0)