There are 4 boys and 3 girls. What is the probability the boys and girls sit alternately?

• ANS- 1/35
  Exp:
  the way of sitting and their respective probabilities are...
  B G B G B G B
  (4/7)*(3/6)*(3/5)*(2/4)*(2/3)*(1/2)*(1/1)=1/35
• 13 years agoHelpfull: Yes(24) No(12)
• 4 boys and 3 girls
  i.e
  4/7*3/6*3/5*2/4*2/3*1/2*1/1=1/35
  so, 1/35 is the answer
• 13 years agoHelpfull: Yes(18) No(3)
• B G B G B G B
  probability of sitting alternately=(3!*4!)/7!=1/35 ANS..
• 10 years agoHelpfull: Yes(12) No(1)
• You have 7! (1*2*3*4*5*6*7) ways of arrangement.
  From those 3!*4! (the ways of arranging the girls * the ways of arranging the boys) ways of arranging the 4 boys and 3 girls alternately.
  Thus the probability is 3!4!/7! = 1/35
• 10 years agoHelpfull: Yes(2) No(0)
• -b-b-b-b-
  total possible places for total boys and girls are=7!=5040
  possible places for sitting girls are=5p3=30
  so probability will be=30/5040=1/168
• 13 years agoHelpfull: Yes(1) No(28)
• ANS- 1/35
  Exp:
  the way of sitting and their respective probabilities are...
  B G B G B G B
  (4/7)*(3/6)*(3/5)*(2/4)*(2/3)*(1/2)*(1/1)=1/35
  
• 9 years agoHelpfull: Yes(0) No(0)
• 24*6=144........ four boys can be arranged in 24 ways and three girls in 6 ways
  
• 8 years agoHelpfull: Yes(0) No(2)
• 4! * 3! 1
  _______ = _____
  7! 35
• 6 years agoHelpfull: Yes(0) No(0)