A sperical ball of radius 7cm is kept on the floor. It is to be covered by a right cylinder open at one end. Find the volume and the surface area of the cylinder if the cylinder just covers the ball

• As the Cylinder just covers the ball,
  so Radius of ball=Radius of the cylinder=r=7
  Height of the cylinder=2r=14
  Volume of cylinder=Pi*r^2*h=(22/7)*7^2*14=2156 cm^3
  Surface area of cylinder=2*Pi*r(r+h)=2*(22/7)*7(7+14)=924 cm^2
• 11 years agoHelpfull: Yes(2) No(0)
• rad of ball is 7cm.
  hence height and rad of cylindr is 7cm is enough to cover the ball.
  vol of cylindr= pi*r^2*h= 1077cc
  surface area of cylindr= 2pi*r*h= 307.8sq cm.
  
• 11 years agoHelpfull: Yes(0) No(1)
• As the Cylinder just covers the ball,
  so Radius of ball=Radius of the cylinder=r=7
  Height of the cylinder=2r=14
  Volume of cylinder=Pi*r^2*h=(22/7)*7^2*14=2156 cm^3
  Surface area of cylinder=2*Pi*r*h=2*(22/7)*7*14=615.752 cm^2
  
• 11 years agoHelpfull: Yes(0) No(0)