From a group of 7 men and 6 women ,five person are to be selected to form a committee so that at least 3 men are there on the committee.in how many ways can it be done?
a) 564
b) 645
c) 735
d) 756

• (7c3*6c2)+(7c4*6c1)+(7c5*6c0)
  =756.
• 11 years agoHelpfull: Yes(24) No(0)
• (7c3*6c2)+(7c4*6c1)+(7c5*6c0)=756
• 11 years agoHelpfull: Yes(3) No(0)
• 7c3*6c2
  35*15=525 this the ans.
• 11 years agoHelpfull: Yes(0) No(8)
• We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).
  
  Required number of ways = (7C3 x 6C2) + (7C4 x 6C1) + (7C5)
  = 7 x 6 x 5 x 6 x 5 + (7C3 x 6C1) + (7C2)
  3 x 2 x 1 2 x 1
  = 525 + 7 x 6 x 5 x 6 + 7 x 6
  3 x 2 x 1 2 x 1
  = (525 + 210 + 21)
  = 756.
• 10 years agoHelpfull: Yes(0) No(0)