If a-b=3 and a^2+b^2=29,find the value of ab.

a) 10
b) 12
c) 15
d) 18

• we know (a-b)^2= a^2 + b^2 - 2ab
  3^2=29-2ab
  ab=20/2=10
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• 10 IS THE ANSWER
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• 5-2=3
  (5)^2+(2)^2=29
  5*2=10
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• (a-b)^2=a^2+b^2-2ab
  9=29-2ab
  -20=-2ab
  ab=10
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• 10
  as a=5,b=2 and a=-2,b=-5 their product is 10
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• a=5,b=2
  a-b=(5-2)=3
  a^2+b^2
  5^2+2^2=25+4
  =29.
  5*2=10
  ans is 10.
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