A is 20 percent more efficient then b.if the two person can complete a piece of work in 60 days.in how many days.A working alone can complete the work

a) 80
b) 90
c) 100
d) 110

• As per ques,a=(120/100)*b
  =>a=(6/5)*b
  therefore,b=(5/6)*a
  Now,a & b complete the work in 60 days
  =>(1/a)+(1/b)=60
  =>(1/a)+(5/6a)=60
  =>a=110
• 10 years agoHelpfull: Yes(36) No(17)
• a=(100+20)/100)b
  a=1.2b
  a=6/5b
  b=5/6a
  1/a+1/b=1/60
  1/a+5/6a=1/60
  11/6a=60
  a=110
  
• 10 years agoHelpfull: Yes(11) No(9)
• A+B=1/60
  A=(6/5)B
  6x+5x=1/60
  x=1/660
  A's 1 day work=6*1/660=1/110
  A can complete work in 110 days
  
• 10 years agoHelpfull: Yes(11) No(2)
• @arindam : why did you take 1/b=5/6a ??? because
  b=5a/6 so 1/b must be 6/5a..!!!
• 10 years agoHelpfull: Yes(9) No(0)
• A's 1 day work + B 's 1 day work= 1/60
  since , A=(1+20/100)B => A=6/5B
  A+B=1/60
  dividing both sides by A
  1+B/A=1/60A
  A=1/110
  A=110 days
  
  
  
• 8 years agoHelpfull: Yes(2) No(0)
• @arindam why dont you consider 20% efficient as taking lesser time to complete the same work?
  
• 10 years agoHelpfull: Yes(1) No(1)
• 110 days ............as let us think b completes y amount pf work in one day then a completes y+y/5=6y/5 s combining a and b they perfoem 11y/5 amount of work per days they completed work in 60 days so total work=60(11y)/5=660y/5
  now only a work speed=distance/time so time=d/s=660y/5/6y/5=110 days
• 10 years agoHelpfull: Yes(1) No(0)
• as question b=(5/6)a
  a+(5/6)a=(11/6)a
  a:(11/6)a::60:x
  x=(11/6)a*60/a=110
• 10 years agoHelpfull: Yes(1) No(0)
• @ISHAN yes man that will be also correct,but i approached the problem that way nd so continued it in my manner,taking 20% efficiency will increase da efficiency of da problem..:)
• 10 years agoHelpfull: Yes(1) No(0)