A is 20 percent more efficient then b if the two person can complete a piece of work in 60

a=(100+20)/100)b
a=1.2b
a=6/5b
b=5/6a
1/a+1/b=1/60
1/a+5/6a=1/60
11/6a=60
a=110
11 years agoHelpfull: Yes(11) No(9)
A+B=1/60
A=(6/5)B
6x+5x=1/60
x=1/660
A's 1 day work=6*1/660=1/110
A can complete work in 110 days
11 years agoHelpfull: Yes(11) No(2)
@arindam : why did you take 1/b=5/6a ??? because
b=5a/6 so 1/b must be 6/5a..!!!
11 years agoHelpfull: Yes(9) No(0)
A's 1 day work + B 's 1 day work= 1/60
since , A=(1+20/100)B => A=6/5B
A+B=1/60
dividing both sides by A
1+B/A=1/60A
A=1/110
A=110 days
9 years agoHelpfull: Yes(2) No(0)
@arindam why dont you consider 20% efficient as taking lesser time to complete the same work?
11 years agoHelpfull: Yes(1) No(1)
110 days ............as let us think b completes y amount pf work in one day then a completes y+y/5=6y/5 s combining a and b they perfoem 11y/5 amount of work per days they completed work in 60 days so total work=60(11y)/5=660y/5
now only a work speed=distance/time so time=d/s=660y/5/6y/5=110 days
11 years agoHelpfull: Yes(1) No(0)
as question b=(5/6)a
a+(5/6)a=(11/6)a
a:(11/6)a::60:x
x=(11/6)a*60/a=110
11 years agoHelpfull: Yes(1) No(0)
@ISHAN yes man that will be also correct,but i approached the problem that way nd so continued it in my manner,taking 20% efficiency will increase da efficiency of da problem..:)
11 years agoHelpfull: Yes(1) No(0)

A is 20 percent more efficient then b.if the two person can complete a piece of work in 60 days.in how many days.A working alone can complete the work

a) 80
b) 90
c) 100
d) 110