A boat M leaves shore A and at the same time boat B leaves shore B. They move across the river. They met at 500 yards away from A and after that they met 300 yards away from shore B without halting at shores. Find the distance between the shore A & B.

• 1) A------------------500--|-----------(d-500)----------------------B
  2) A----------------(d-300)--------------|-300----------------------B
  let a and b are the speeds of boats m,b
  in first meet,
  time taken by m=time taken by b
  500/a=(d-500)/b
  a/b=500/(d-500)-----------------(1)
  in second meet,
  the boat m should travel (d-500)+300
  then boat b should travel 500+(d-300)
  time taken to travel from firstmeet to second meet of m=time taken to travel from firstmeet to second meet of b
  (d-500)+300/a=500+(d-300)/b
  d-200/d+200=a/b
  from (1)
  (d-200)/(d+200)=500/(d-500)
  (d-200)(d-500)=500(d+200)
  d^2-700d+1000=500d+1000
  d^2-1200d=0
  d(d-1200)=0
  d=1200
  
• 9 years agoHelpfull: Yes(3) No(0)