Given 3 lines in the plane such that the points of intersection from a triangle with sides of length 20, 20 and 11 the number of points equidistant from all the 3 lines is
0
3
1
4

• 4
  1 point inside the triangle and other three outside the triangle
• 12 years agoHelpfull: Yes(24) No(3)
• ans is 4.
  for any triangle there is 1 incenter,3 excenters..
  so incircle,excircles touching 3 sides of triangle that means that centers of circles are equidistant from all 3 sides of triangle..
  so that points are incenter,3 excenters.
  
• 12 years agoHelpfull: Yes(18) No(0)
• 10800 by simple exponential calculation
  
  
• 12 years agoHelpfull: Yes(0) No(21)
• 1 incircle and four excircles would be drawn to that triangle,where the thier centre colud equidistant from all the sides
• 9 years agoHelpfull: Yes(0) No(0)