There are two boxes, one containing 24 red balls and the other containing 38 green balls. You are allowed to move the balls between the boxes so that when you choose a box at random and a ball at random from the chosen box the probability of getting a red ball is maximized. This maximum probability is
.50
.39
.69
.19

• 0.69
  we will keep 1 red ball in 1 box so that if we choose that box...
  the prob.=1/2 * 1
  rest 23 balls will be in 2nd box so maximum prob. to select that box is
  1/2 * 23/61
  sum of both will be the answer
• 13 years agoHelpfull: Yes(20) No(3)
• 0.69 its 1/2[1]+1/2[23/61]
• 13 years agoHelpfull: Yes(5) No(0)
• here required maximum probability
  so put all the red balls in 1 box and green in other
  prob. of choosing 1 box =(1/2)
  so finally max prob= (1/2)*1= 0.50
  
• 13 years agoHelpfull: Yes(2) No(6)