There are two water tanks A and B , A is much smaller than B. While water fills at the rate of one litre every hour in A, it gets filled up like 10,20,40,80,160 .. in tank B. (At the end of first hour, B has 10 litres, second hour it has 20, and so on). If tank B is 1/8 filled after 23 hours, what is the total duration required to fill it completely?
27 hours
25 hours
26 hours
3 hours

• rate of A = 2times of B
  till now 23 hrs have been completed and tank B is 1/8 filled.
  hence in next one hr 2 times of it would get filled...i.e. (1/8)*2=1/4
  after another one hr=(1/4)*2=1/2
  another one hr=(1/2)*2=1 (fully filled)
  it required extra 3 hrs.
  hence ans is 23+3=26 hrs.
  TIP: try to make the fraction part 1 by multiplying with the factor given in the ques. no of times u multiplied to make it no= no of extra hrs.
• 13 years agoHelpfull: Yes(8) No(1)
• 1/8 - 23
  1/4 - 24
  1/2 - 25
  1 - 26
  Ans: 26
  
  Everytime the water filled double..
• 13 years agoHelpfull: Yes(5) No(0)
• 1/8=1/2^3
  1/8 filled after 23 hours
  So it will totally filled up the tank 23+3=26 hours
• 13 years agoHelpfull: Yes(2) No(0)
• the tank fills double in every 1 hour. so, if in 23 hours the tank is 1/8 filled.....
  therefore in 24hrs== 2*1/8=1/4
  25hr= 1/2
  26th hour= 1...therefore the tank is full
• 13 years agoHelpfull: Yes(1) No(0)