16 men can complete a work in 24 days , while 48 children can do it in 16 days.12 men started the work , aftr 14 dats 12 children joined the.in how many days will all of them do the remaining work ?

• 16M=24D so 1M=384D
  48CH=16D so 1CH=768D
  so here we got 1M=2Ch
  12M*14D=168D of work completed
  remaining work 384D-168D=216D
  12 childrens are added means 12CH=6M
  so 12M+6M=18M
  18M can complete 216D work in=216/18=12Days
  
• 10 years agoHelpfull: Yes(20) No(2)
• 16 men can complete work in 24 days so 1 men 1 days work =1/16*24
  similarly 1 children 1 days work=1/48*16
  so 12 men work=1/16*24*12=1/32
  14 day work of 12 men=1/32*14=7/16
  total remaining work=9/16
  12 children 1 day work=1/64
  total 1 days work of 12 children and 12 men=1/32+1/64=3/64
  so remaining work 9/16 can be done in 64/3*9/16=12 ans
• 10 years agoHelpfull: Yes(9) No(1)
• ans : 12
  M1*D1=M2*D2=> 1 man=2 children then we have to find total work.
  16M*24=16*2*24=768
  12 men started work so 12m*14=12*2*14=336
  
  768-336=432
  then 12M+12C=12*2c+12C=36
  remaing work/36
  =432/36
  =12
• 10 years agoHelpfull: Yes(3) No(0)
• 16 men can do in one day=1/24
  1 men can do in one day=1/(16*24)
  similarly 1 child can do in one day=1/(16*48)
  12 men can do work in 14 days=14*(12/16*24)=7/16
  remaining work = 9/16
  12 men and 12 child can do in one day = (1/32)+(1/64)=(3/2)*(1/32)
  remaining work can be done = (9/16)*32*(2/3)= 12
• 10 years agoHelpfull: Yes(0) No(1)
• hey is there any shortcut for this kind of time and work problems plz
• 9 years agoHelpfull: Yes(0) No(0)