(40*40*40-31*31*31)/(40*40+40*31+31*31)=?

• it is of (a^3-b^3)/(a^2+ab+b^2) formula.so the soln would be a-b so 40 - 31 wil be the answer
• 13 years agoHelpfull: Yes(24) No(3)
• a^3-b^3=(a-b)(a^2+b^2-ab)
  thus
  ans=a-b
  = 40-31
  =9
• 13 years agoHelpfull: Yes(16) No(2)
• it is simple expansion of a^3-b^3
  let a3 denotes acube
  a3-b3=(a-b)(a2+ab+b2)
  a-b=(a3-b3)/(a2+ab+b2)
  compare with the given a=40 and b=31
  answer=a-b=40-31=9
• 13 years agoHelpfull: Yes(12) No(1)
• (a^3-b^3)=(a-b)(a^2+a*b+b^2)
  Here, a=40, b=31. So the answer is a-b= 9.
• 13 years agoHelpfull: Yes(6) No(0)
• 40-31=9
  
  we can write the givn as
  (40-31)(40^2-40*31+31^2) / (40^2-40*31+31^2)
• 13 years agoHelpfull: Yes(4) No(1)
• 34209/3801=9
• 13 years agoHelpfull: Yes(2) No(10)