64 1614 1116114 31163114 132116132114 What is the number of digits in the next term in this sequence?
1-20
2-12
3-16
4-18

• 62-2digits
  1614-4digits
  1116114-7digits
  31163114-8digits
  132116132114-12digits
  so sequence is 2,4,7,8,12,?
  2+5=7 &7+5=12
  4+4=8 &8+4=12
• 11 years agoHelpfull: Yes(32) No(52)
• Solution :
  
  Given sequence is 64 1614 1116114 31163114 132116132114.
  It is a look-and-say sequence.
  
  The first term is 64.
  The next term is the description of the first term, 1614 (one 6 one 4).
  2nd term is described in the 3rd term as 11161114, (one 1 one 6 one 1 one 4).
  Then the 4th term is 31163114 ( three 1 one 6 three 1 one 4).
  And the 5th term is 132116132114 (one 3 two 1 one 6 one 3 two 1 one 4)
  Then the required term is 11131221161113122114 (one 1 one 3 one 2 two 1 one 6 one 1 one 3 one 2 two 1 one 4).
  Therefore the number of digits in the required term is 20.
• 11 years agoHelpfull: Yes(22) No(2)
• first term has 2 terms and 2nd term contains the digits in the first term and so on
  
  ans is 20
• 11 years agoHelpfull: Yes(9) No(13)
• ans is 20
  is like
  64-6 is one tmes & 4 is 1 times so the next number was-1614
  similarly for 132116132114--11131221161113122114
• 11 years agoHelpfull: Yes(7) No(7)
• answer: 2- 12
  count the no. of digits, then series is
  2,4,7,8,12,...
  difference between alternate terms is common
• 11 years agoHelpfull: Yes(5) No(11)
• 11131221161113122114 is the next term so the number of digits is 20
  
• 11 years agoHelpfull: Yes(1) No(1)
• No. Of digits in 1st term=2
  No. Of digits in 2nd term=4
  3rd term=7
  4th term=8
  5th term=12
  6th term must consist 12 digits
  Its in the series like:-
  1st term +5=3rd term which is 2+5=7
  3rd term +5=5th term which is 7+5=12
  And all the even place term will be added with 4 like
  2nd term +4=3rd term which is 4+4=8
  3rd term +4=5th term which is 8+4=12
  So answer is 12!!
• 8 years agoHelpfull: Yes(0) No(2)