man sold 12 candies in 10 had loss of a then again sold 12 candies at 12 had profit of

Now for Profit ((S.P-C.P)/C.P)*100)
and in Loss ((C.P-S.P)/C.P)*100)
in above problem 10$ is s.p in case of loss and 12$ is s.p in case of profit
and as we can see loss% and profit% are equal then we can write
(x-10)=(12-x)...(here 100 and C.P will get cancel)
x=11
put x=11 in any equation and you ll get 100/11
10 years agoHelpfull: Yes(6) No(0)
let c.p. of one candle is x.
in case of loss
S.P. (10/12)/C.P. (x) = (100-a)/100..................(1)
in case of profit
S.P. (12/12)/C.P. (x) = (100+a)/100..................(2)

equation (1)/(2)....
10/12= (100-a)/(100+a):
a=9.09
9 years agoHelpfull: Yes(2) No(0)
let c.p of 12 candies=x
if loss then
a%=(x-10)*100/x-(2)
if profit then
a%=(12-x)*100/x-(1)
equating eqn(1)&(2)
x=11
and the solution is 100/11
10 years agoHelpfull: Yes(0) No(1)
SOLUTION
10*(100+a)/12 = (100-a) ; a= 100/11=9.09
9 years agoHelpfull: Yes(0) No(1)

man sold 12 candies in 10$ had loss of a% then again sold 12 candies at 12$ had profit of a% find the value of a