A child was looking for his father.He went 90 mts in the east before turning to his right.He went 20 mts before turning to his right again to look for his father to his uncles place 30 mts from this point his father was not there.from here he went 100 mts to the north before meeting his father in the street how far did the son meet his father from the starting point?

• 100 meters north-east
• 10 years agoHelpfull: Yes(13) No(0)
• 100 mts
  overall he went 80 mts. north
  and 60 mts. east
  total displacement=100
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• 100 meters.from the starting point he went 90 meters straight.then he turned to his right went 20 meters straight.again he turned to his right and went 30meters(his uncle's place).from that point he went towards north 100 meters.so,
  AB=sqrt((100-20)^2 + (90-30)^2)=100
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• 100 mts north-east
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• can anyone explain this clearly........
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• son would meet his father by travelling 100 kms.
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• i am not getting the question.... can anyone help
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