IBM Company Numerical Ability Alligation or Mixture

two glasses were filled with 1/3 and 1/4 milk. they were filled with water &then mixed in tumbler. what is the percentage of milk in the resultant.

Read Solution (Total 3)

total milk =1/3 + 1/4 =7/12
total water = 2/3 + 3/4 = 17/12
total vol = 2
so % of milk =(7/12/2)*100=175/6
11 years agoHelpfull: Yes(28) No(3)

water in 1st glass=1-1/3=2/3
water in 2nd glass=1-1/4=3/4
now in resultant
total milk =1/3+1/4=7/12
total water=2/3+3/4=17/12
total solution=7/12+17/12=24/12
required %=(7/12)*100/(24/12)=29.17
11 years agoHelpfull: Yes(25) No(0)
water in first glass= 1-1/3
water in second glass= 1-1/4
total milk in tumbler = 1/3 + 1/4=7/12
total water in tumbler = 2/3 + 2/4 = 14/12

total solution in tumbler = total milk + total water, i.e. 7/12 + 14/12 = 21/12

% of milk = milk in tumbler/(milk+water) * 100%
= (7/12) / (21/12) * 100 =33.33 %
11 years agoHelpfull: Yes(3) No(20)

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