TCS
Company
Numerical Ability
Algebra
if p(x)=ax^4+bx^3+cx^2+dx+e has roots at x=1,2,3 and 4 ,and p(0)=48, what is p(5)?
Read Solution (Total 3)
-
- given polynomial eqn may be written as..a(x-1)(x-2)(x-3)(x-4)
from ques,a(0-1)(0-2)(0-3)(0-4)=48
a=2
substitute the value of a and 5 to get p(5)=48 - 11 years agoHelpfull: Yes(33) No(3)
- as the root are 1 2 3 4
equation is k*(x-1)*(x-2)*(x-3)*(x-4)=0
when x=0 then k=2
so put keep k as 2 and put in above equation
x=5 know so again p(5)=48 - 11 years agoHelpfull: Yes(7) No(1)
- k{(x-1)(x-2)(x-3)(x-4)}=ax^4+bx^3+cx^2+dx+e
a=2
b=-20
c=70
d=-100
e=48
p(5)=48 - 11 years agoHelpfull: Yes(2) No(6)
TCS Other Question