if p(x)=ax^4+bx^3+cx^2+dx+e has roots at x=1,2,3 and 4 ,and p(0)=48, what is p(5)?

• given polynomial eqn may be written as..a(x-1)(x-2)(x-3)(x-4)
  from ques,a(0-1)(0-2)(0-3)(0-4)=48
  a=2
  substitute the value of a and 5 to get p(5)=48
• 10 years agoHelpfull: Yes(33) No(3)
• as the root are 1 2 3 4
  
  equation is k*(x-1)*(x-2)*(x-3)*(x-4)=0
  
  when x=0 then k=2
  
  so put keep k as 2 and put in above equation
  
  x=5 know so again p(5)=48
• 10 years agoHelpfull: Yes(7) No(1)
• k{(x-1)(x-2)(x-3)(x-4)}=ax^4+bx^3+cx^2+dx+e
  a=2
  b=-20
  c=70
  d=-100
  e=48
  p(5)=48
• 10 years agoHelpfull: Yes(2) No(6)