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Numerical Ability
Permutation and Combination
A man has 7 friend among them 4 are female and 3 are male. And his wife has 7 friend among them 4 are male and 3 are female. 6 person were invited for party. What is the probability that there were 3 female, 3 male, 3 female friends of man and 3 male friends of his wife?
Read Solution (Total 9)
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- (4c3*4c3)/14c6
- 10 years agoHelpfull: Yes(35) No(9)
- probabiliy of 3female friends of male is 4c3/7c3
probabiliy of 3male friends of female is 4c3/7c3
total 4c3/7c3*4c3/7c3
- 10 years agoHelpfull: Yes(29) No(0)
- 2*4c3/14c6
- 10 years agoHelpfull: Yes(22) No(13)
- 4c3*4c3/7c3*7c3
- 10 years agoHelpfull: Yes(16) No(0)
- ans:-(4c3*4c3)/(14c6)
- 10 years agoHelpfull: Yes(2) No(2)
- 2*4c3/14c6
- 10 years agoHelpfull: Yes(1) No(3)
- 4c3*4c3/14c3
- 10 years agoHelpfull: Yes(1) No(4)
- (4c3/7c3)*2
- 10 years agoHelpfull: Yes(0) No(6)
- 4c3*4c3/7c3*7c3......this answer is wrong because total cases will be selecting 7 friends from a group of 14 people...... who the **** told you to select 3 people from male and three from female....???(its not mentioned..) so correct answer will be 4c3*4c3/14c3
- 10 years agoHelpfull: Yes(0) No(12)
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