The remainder when 2^232 is divided by 43 is?
a)1
b)2
c)42
d)41

• 2^232 = 2^(7*33)*2 = 128^33 * 2 now dividing 128 by 43 we got remainder -1 as 43*3 =129 so remainder = -1^43 *2 =-2 =43-2 =41 is the right ans.hope all of u understand
• 10 years agoHelpfull: Yes(19) No(3)
• 2^232= (2^7)^33.2= 128^33.2
  128 divide by 43 gives -1 rem
  thus rem is -2= 43-2= 41
• 10 years agoHelpfull: Yes(13) No(4)
• i think the answer should be d)41.
  
• 10 years agoHelpfull: Yes(8) No(6)
• ans-- d)41
  
• 10 years agoHelpfull: Yes(5) No(4)
• ans is 41
  2^232=(2^8*29)/43 =(41)^29/43
  rem is 41
• 10 years agoHelpfull: Yes(4) No(1)
• ans is 41 only answering should be like this
  2^232/43=2*2^231/43= 2*(2^7)^33/43= 2*(128)^33/43 using remainder theorem 128 gives -1 remainder by dividing with 43 so 2*(-1)^33/43 remainder will be -2 or 41
• 10 years agoHelpfull: Yes(4) No(2)
• 232/4=58 remainder is 0.and 2^0 is1.1/43 rem is 1
• 10 years agoHelpfull: Yes(3) No(5)
• xplain clerlyyy
  
• 10 years agoHelpfull: Yes(3) No(1)
• ans is 2
  #
  2^232/43=((2^7)^33*2)/43
  
  1*1*1...33times*2/43 will gve u 2 as aremainder
  
• 10 years agoHelpfull: Yes(2) No(2)
• 2^232 can be written as (2^8)^29/43
  2^8 is 256 and 256/43 gives the rem as 41
  so ans is 41
• 10 years agoHelpfull: Yes(2) No(0)
• a)1 as2 has even multiple power
• 10 years agoHelpfull: Yes(1) No(2)
• Please explain!
• 10 years agoHelpfull: Yes(1) No(3)
• ans is 1
  
  
• 10 years agoHelpfull: Yes(1) No(3)
• the answer is 42
  
• 10 years agoHelpfull: Yes(1) No(3)
• ans is d 41
  43-2=41
• 10 years agoHelpfull: Yes(0) No(0)
• 2^231 is dividened by 42
  43-2=41 @ans is 41
• 7 years agoHelpfull: Yes(0) No(0)