ab+a+b=135
bc+b+c=322
ca+c+a=151
then a+b+c=?

• a+b+ab=135 or,a=(135-b)/(1+b)
  
  a+c+ac=151 or, c=(151-a)/(1+a)
  now replacing a=(135-b)/(1+b)
  we get c=(2+19b)/17
  
  b+c+bc=322 or,c=(322-b)/(1+b)
  
  so we can write ((322-b)/(1+b))=((2+19b)/17 or,b^2+2b-288=0 or,b=either -18 or 16
  
  now if b=-18 then a=9 & c=20;
  if b=16 then a=7 & c=18
  
• 11 years agoHelpfull: Yes(20) No(17)
• a=7,b=16,c=18......so a+b+c=41
• 11 years agoHelpfull: Yes(9) No(20)
• @ ankita please explain hoe you got the values of a, b, c?
• 11 years agoHelpfull: Yes(5) No(6)
• Ankita can u pls explain
  
• 11 years agoHelpfull: Yes(4) No(3)
• post the options tooo
• 11 years agoHelpfull: Yes(2) No(5)
• if we take a=7 & b=16 then
  7*16+7+16=135
  now c=18 so
  16*18+16+18=322
  18*7+18+7=151
  
  so a+b+c=7+16+18=41
• 11 years agoHelpfull: Yes(1) No(18)
• 2(ab+bc+ca)+2(a+b+c)=766
  2(250-a-b+300-b-c+216-a-c)+2(a+b+c)=766
  1532-(a+b+c)=766
  2(a+b+c)=766
  a+b+c=383
• 7 years agoHelpfull: Yes(1) No(8)
• a+b+c=307
  
• 11 years agoHelpfull: Yes(0) No(9)