What is the remainder when the number
123456789101112131415161718192021222324252627282930313233343536373
839404142434481
is divided by 45?

• it can be written as 12345......4400+81, since the no 1234....4400 is devisible by both 9 nd 5 so this no will be devisible by 45 now devide 81 by 45 u will get ur remainder as 36.
  ans. 36
• 11 years agoHelpfull: Yes(74) No(1)
• use [n(n+1)]/2 .. !!! [44(44+1)]/2+81 = 44*45/2+81 = 1071. divide 1071 by 45 = 36 as remainder.. !!
• 11 years agoHelpfull: Yes(30) No(12)
• sum of digits at units pace =(1+2+3+4+5+6+7+8+9)= 45
  This occurs 4 times so 45*4= 180
  sum of digits in 41,42,43,44 at units place= 10
  Sum of 10 between 10 and 19= 10*10=100
  sum of 20 between 20 and 29= 20*10=200
  sum of 30 between 30 and 39= 30*10=300
  sum of 40 between 40 and 44= 40 *5=200
  total sum =(180+100+200+300+200+10+81)=1071
  1071/45= 36 remender
• 11 years agoHelpfull: Yes(8) No(2)
• remainder will be
  81-45=36
• 11 years agoHelpfull: Yes(6) No(4)
• divide last 2 numbers by 45..
  so the remainder obtained is 36
• 11 years agoHelpfull: Yes(2) No(0)
• i think 81-45=36
• 11 years agoHelpfull: Yes(1) No(7)
• what is the question
  plz clarify it.
  
• 11 years agoHelpfull: Yes(1) No(1)
• @vivek....y shud v take 81??
• 11 years agoHelpfull: Yes(1) No(0)
• we have series in that questions like 1,2,3,4,56,7,8,9,10,11 ... 44, end is 81 is different from the series 81/45 reminder is 36
• 11 years agoHelpfull: Yes(1) No(0)
• i didnt understand d solutin..can any1 plz explain
• 11 years agoHelpfull: Yes(1) No(0)
• @vikas singh ..how u find that it is divided by 9 ?
• 11 years agoHelpfull: Yes(1) No(0)
• the number can be written as 1234.....4344 + 81. The addition of the digits of 1234...4344 is 270 which is divisible by 9 and the number itself is also divisible by 5, hence divisible by 45. Now 81%45 = 36, hence the answer
• 11 years agoHelpfull: Yes(1) No(0)
• Ans=31
  481-450=31
  
• 11 years agoHelpfull: Yes(0) No(4)