The Radius of a circle is 20 cm and the length of two chords in it are 32 cm and 24 cm .Find the distance between two chords???

• IF CORDS ARE IN THE SAME SIDE
  THEN THE DISTANCE WILL BE = 4
  
  AND IF IN THE OPPOSITE SIDE ,DISTANCE =28
  
  
• 11 years agoHelpfull: Yes(14) No(0)
• ANS: 28 cm (16 cm + 12 cm)
  
  hy ^ 2 = side1 ^ 2 + side2 ^ 2
  
  1st triangle make as: (20 ^ 2) =(16 ^ 2) + (lenght 1 ^ 2)
  so, by solving length 1 = 12 cm
  
  2nd triangle make as: (20 ^ 2) =(12 ^ 2) + (lenght 2 ^ 2)
  so, by solving length 2 = 16 cm
  
  length 1 + length 2 = 12 + 16 cm = 28 cm
  
  
• 11 years agoHelpfull: Yes(13) No(3)
• By using Pythagoras theorem,
  Distance between centre and 32cm chord=12cm
  distance between centre and 24cm chord=16cm
  so, total distance=4cm or 28cm
• 11 years agoHelpfull: Yes(6) No(0)
• ans= sqrt(400-256)+sqrt(400-24)=28cm
• 11 years agoHelpfull: Yes(2) No(0)
• Ans will be 28 cms. 20^2=16^2+x^2 => x=12
  Similarly, 20^2=12^2+y^2 => y=16.
  Therefore distance = 12+16=28 cms.
• 11 years agoHelpfull: Yes(2) No(0)
• distance btween two chords if they are on same side=16-12=4cm.
• 11 years agoHelpfull: Yes(2) No(2)
• if 2 chords are in same side distance should ve 4cm
  and if they are in opp dire it may be 28 cms
• 11 years agoHelpfull: Yes(2) No(0)
• 4 cms
  The distance between the chords had been asked
  so, 16-12=4cms
  
• 11 years agoHelpfull: Yes(0) No(1)
• just split them into right angled triangles and find other side using hypotenuse as given radius!!!!
• 11 years agoHelpfull: Yes(0) No(0)