Three dice are rolled, how many ways are there such that the total sum is 13 ?

• 1,6,6->3!/2=3
  3,5,5->3!/2=3
  4,4,5->3!/2=3
  2,5,6->3!=6
  4,6,3->3!=6
  
  Total sum=3+3+3+6+6=21
• 11 years agoHelpfull: Yes(27) No(1)
• Okay! Its 21
  1,6,6
  2,5,6
  3,4,6
  3,5,5
  4,4,5
  
  So 3!*5-(3!/2! *3)=21
• 11 years agoHelpfull: Yes(18) No(1)
• In detail,the above five cases can be arranged in 3! ways..and hence 3!*5=30
  (3!/2!)* 3 is because in (1,6,6);(3,5,5);(4,4,5)......2 digits are repeated.
  hence 30-9=21
  
• 11 years agoHelpfull: Yes(4) No(1)
• 1,6,6->3!/2=3
  3,5,5->3!/2=3
  4,4,5->3!/2=3
  2,5,6->3!=6
  4,6,3->3!=6
  
  Total sum=3+3+3+6+6=21
• 11 years agoHelpfull: Yes(1) No(1)
• 17/6^3 as 17 are the no. of cases
  
• 11 years agoHelpfull: Yes(0) No(1)
• Ans is 25..
  (1,1,1,2,2,2,3,3,3,4,4,4)=4
  3!*5=30
  (3!/2!)*3=9
  so 4+30-9=25
• 11 years agoHelpfull: Yes(0) No(3)
• 21... combination are
  1,6,6=3 ways
  2,6,5=6 ways
  3,6,4=6 ways
  4,4,5=3 ways
  5,5,3=3 ways
  total 21 ways
• 11 years agoHelpfull: Yes(0) No(0)