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1!+2!+....50! =?
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- sigma(n*n!)=(n+1)!-1 from n=1 to n
thus, for sigma(n!)..we can write it as (sigma(n*n!)/n), which is equal to ((n+1)!-1)/n.
now replace n=50
we get (51!-1)/50
this is the answer. - 11 years agoHelpfull: Yes(6) No(17)
- summation of n factorial is given by the formula L!n(left factorial of n) which is defined as "permutation of n objects such that no object appears in its natural place" Ex:!3=2,since (1,2,3) be natural order,(2,3,1),(3,1,2) are only possible...L!n is also given by n!/e => !50=50!/e=1.118872e+64
- 11 years agoHelpfull: Yes(2) No(2)
- in an A.P sum of first and last term is equal to the sum first 2nd term and 2nd last term viceversa till all the values are added
in this example:1!+50!=3.04140932*10^64
here num of values == 50
hence we have 50/2 values =25
multiply 25 with 3.04140932*10^64=7.6035233*10^65 - 11 years agoHelpfull: Yes(1) No(0)
- apply summation to n th term to get the value ...so we get 22100
- 11 years agoHelpfull: Yes(0) No(9)
- apply to this formula... n(n+1)(2n+1)/6....
- 11 years agoHelpfull: Yes(0) No(19)
- pls send me tcs apti papers 2013.......my id-rharsh170@gmail.com
- 11 years agoHelpfull: Yes(0) No(10)
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