Two identical taps fill 2/5 of a tank in 20 minutes. When one of the taps goes dry in how many minutes will the remaining one tap fill the rest of the tank ?

• ans 60 mins
  2/5 of tha tank is filled in 20 mins by 2 taps.
  so,1 tap can fill tha same amt in 40 mins.
  remaining(1-2/5=3/5) will be filled in 60 mins by 1 tank
• 13 years agoHelpfull: Yes(29) No(37)
• ans:15 mins
  2/5 of the tank is filled by 2 identical taps in 20 mins.
  remaining part of the tank left is (1-2/5)=3/5
  so time taken by 1tap for filling 2/5th of tank=(20/2)=10 mins (bcoz two taps are identical)
  hence time taken by 1 tap to fill the entire tank=10*5/2=25 mins
  so, time taken to fill the remaining 3/5th of the tank will be = 25*3/2=15 mins
• 9 years agoHelpfull: Yes(14) No(12)
• 2/5 tank is filled by 1 tank in 40 mins..
  so
  remaining 3/5 tank will be filled in (40* 5/2 * 3/5 )= 60 minutes
• 12 years agoHelpfull: Yes(4) No(15)
• Two tap fill the tank 2v/5 in 20 minutes.
  Each tap fills v/5 in 20 minutes.
  Left volume = 3v/5 => 3*20 = 60 minutes.
  Hence "E" is the answer.
• 8 years agoHelpfull: Yes(2) No(5)
• 2/5=20 mins
  2/5+3/5 =5/5 .....which is equal to one full tank
  each pipe flows water for 20 mins .....
  and so it takes 3*20 min of time to fill the remaining tank with one pipe
  60 is the ans
• 7 years agoHelpfull: Yes(0) No(1)