The no. of bacteria was rising exponentially. At 3pm it is 1000, at 5 pm it is 4000, then how many r there at 8 pm???

• hence its rising exponentially....
  3pm-1000
  4pm-2000
  5pm-4000
  this is series of gp
  where
  n=6{3,4,5,6,7,8} term
  r=2000/1000=>2
  a=1000
  number of bacteria at 8pm=a*r^(n-1)
  =1000*2^(6-1)
  =1000*32
  =32000 bacteria
• 11 years agoHelpfull: Yes(21) No(0)
• 4000/1000= 4
  apply this formula =K*T to power 0
  1000*2^2= 4000
  4000*2^3=32000
• 11 years agoHelpfull: Yes(3) No(0)
• 4000=1000(1+x/100)^2
  so x=100%
  bacteria at 8pm will be = 4000(1+100/100)^3=32000
• 11 years agoHelpfull: Yes(3) No(0)
• 32000 is correct
  
• 11 years agoHelpfull: Yes(2) No(0)
• 3pm=1000
  5pm=4000
  2h=3000
  1h=1500
  3h=1500*3=4500
  8pm
  4000+4500=8500
  
• 11 years agoHelpfull: Yes(2) No(8)
• as it is clear 4m d qstn dat d growth of bacteria is xponentially ,so A.P,G.P can b taken into account.
  hence ((1000)^x)^x=4000
  so, x=1.095
  now
  accordin 2 qstn the ans is=(((4000)^x)^x)^x=(4000)^(x^3)=(4000)^(1.095^3)=
  53612.. x=exponential factor by which the bacteria grows per hour......
  
• 11 years agoHelpfull: Yes(0) No(0)