The faces of a cube are numbered from 6 to 11 in such a way that the sum of the

17, 6+11=17
7+10=17
8+9=17
11 years agoHelpfull: Yes(2) No(0)
the faces to be given are (6,11) (7,10) (8,9)
therfore the sum is 17
11 years agoHelpfull: Yes(2) No(0)
@DEVIKA.R:
A cube has 6 faces which are numbered as 6,7,8,9,10,11.this will have 3 opposite faces
given that the numbers are aranged in such a way that sum of numbers in 1st oppsite face is equal to sum of numbers in 2nd opposite face and also equal to sum of numbers in 3rd opposite face
therfefore the possible case is (6+11,7+10,8+9) where the sum of opposite faces is equal to 17
11 years agoHelpfull: Yes(2) No(0)
17,,

6+11,7+10 and 8+9
11 years agoHelpfull: Yes(0) No(0)
EXPLAIN IN DETAIL
11 years agoHelpfull: Yes(0) No(0)
17
10+7 =17
9+8 = 17
11+6 = 17
10 years agoHelpfull: Yes(0) No(0)

The faces of a cube are numbered from 6 to 11 in such a way that the sum of the numbers on opposite faces is the same. What is this sum?
a. 17
b.11
c.8.5
d.6
e.51