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A drinks machine offers three solutions Tea, Coffee or Random but the machine has been wired up wrongly so that each button does not give what it claims. If each drink costs Rs.50, what is the minimum amount of money that must be spent to determine with certainty the correct labeling of the buttons?
Options
a)Rs. 100
b)Can not be determined from the given information
c)Rs 150
d)Rs 50
Read Solution (Total 7)
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- answer is Rs 50.
first we spent on random label.As it is wrongly labeled there are two possible ways of getting drink.That may be tea or coffee.If it is tea then swap the random&tea positions.As coffee is also wrongly labeled so that it must be random.now exchange the coffee&random positions.same solution if the obtained drink is coffee also. - 11 years agoHelpfull: Yes(25) No(2)
- in place of tea we can obtain either tea(random) or coffee.
if we pressed tea if we obtained tea it means that it is random.
so the remaining are coffee=tea, random=coffee.
else if we obtained coffee from tea button. it may be from random or coffee button so if we now press coffee if it obtains tea then the only option is tea=random &random= coffee.or else if we obtained coffee there it means it is random sotea=coffee &random=tea.
so a minimum of 100rs. is required
ans:a - 11 years agoHelpfull: Yes(4) No(6)
- ans is 50. first of all there will be 2 situations possible. Tea label giving coffee, coffee giving random and random giving tea OR tea label giving random, coffee giving tea and random giving coffee. so if we go to tea label and it gives coffee, then we surely know that coffee will give random and random will give tea as no label is marked correctly.
- 11 years agoHelpfull: Yes(2) No(1)
- c because whatever may be the solution it costs Rs50
- 11 years agoHelpfull: Yes(2) No(3)
- suppose if u press tea button : coffee comes (50 rs )
if u press coffee button : tea comes (50 rs)
so total 100 spent then u can guess what will come if u press Random button
; - 11 years agoHelpfull: Yes(1) No(3)
- @SAHANA plzzz tell the right answer......??????
- 11 years agoHelpfull: Yes(1) No(0)
- its a)100. by checking one button for twice,it will give correct labeling.
for example, if we press button labelled as coffe, and we get tea.
second time also we get the tea, then the tea label will be stick to that button and
remaining button that have labeled random will b placed at the button from which we have got the label "tea".
the remaining will b coffee. - 11 years agoHelpfull: Yes(1) No(3)
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