in a 2 digit number the units place is one more than 4 times the digit in ten's place.if the difference between the number formed by interchanging the digit of the number and the original number is 34 more than the original number,find the 2 digit number
a) 15
b) 29
c) 33
d) none of these

• by verifying the answers +1
  92-29=29+34
  and 9= 4*2+1
• 10 years agoHelpfull: Yes(10) No(3)
• Let the two digit number be 10X + Y ...(1)
  (ten's digit is X and unit's digit is Y)
  Unit's digit is 1 more than 4 times the ten's place digit
  Therefore, i.e Y = 4X + 1 ...(2)
  
  Substituting (2) in (1), the two digit number becomes 10X + (4X + 1) ...(3)
  The number after interchanging the digits is 10(4X + 1) + X ...(4)
  
  From question data, we know that the difference between digits interchanged number and actual number is 34 more than the actual number
  
  i.e 10(4X + 1) + X - (10X + (4X + 1)) = 34 + (10X + (4X + 1))
  40X + 10 + X - 10X - 4X - 1 = 34 + 10X + 4X + 1
  30X - 3X + 9 = 34 + 10X + 4X + 1
  27X + 9 = 34 + 10X + 4X + 1
  27X + 9 = 34 + 10X + 4X + 1
  27X - 14X = 35 - 9
  13X = 26
  X = 2.
  Substituting X = 2 in (3), we get the required two digit number 10X + (4X + 1) = 20 + 8 + 1 = 29.
  Hence the answer is 29.
• 10 years agoHelpfull: Yes(6) No(1)
• ans is d>non of these
  let no=10x+y
  here y=4x+1
  hence
  [10*(4x+1)+x]-[10x+(4x+1)]=[10x+(4x+1)]+34
  
  solving x=74/13
  
• 10 years agoHelpfull: Yes(4) No(6)
• @MD AFSAR ALI : - Solving YOUR equation, x values to 2.
  Please do check your answer.
  
  Answer is 29.
• 10 years agoHelpfull: Yes(3) No(3)
• let 10's digit no is x, then unit place digit is 4x+1 Number= (10*x)+(4x+1)
  now solve (10(4x+1)+x)-(10x+4x+1)=34
• 10 years agoHelpfull: Yes(1) No(4)
• according to 1st condition 5=1*4+1 ,hence option a satisfies again 9=2*4+1 satisfies 1st condition.now (51-15)=36 not equals to 34 and 92-29=63 not equals to 34.so both conditions are not being satisfied.. so answer d) none of these..
  
• 10 years agoHelpfull: Yes(1) No(1)