a car travelling 5/7th of its actual spee covers 42km in 1hr 40min 48 sec. wat is d actual speed of d car?
a) 30kmph
b) 35kmph
c) 25kmph
d) 40kmph

• b. 35kmph
  Speed of the train(kmph)=42/[(1*3600+40*60+48)/3600]=25
  Actual speed of d car=25/(5/7)=35 kmph
  
  
• 10 years agoHelpfull: Yes(15) No(1)
• ans-35kmph
  let actual speed be x kmph.
  we know speed*time=distance
  (5x/7)*(126/75)=42
  solving x=35kmph
  here time=1h40m48s=1+(40/60)+(48/3600)=126/75
  
• 10 years agoHelpfull: Yes(7) No(2)
• speed of car=42000/6048=6.944
  let actual speed = x
  5x/7=42000/6048
  x=294000/30240=9.722m/sec=35kmph
  
• 10 years agoHelpfull: Yes(5) No(0)
• answer 35km/h
• 10 years agoHelpfull: Yes(1) No(0)
• option B 35kmph
  let actual speed is d kmph
  with (5/7)d=[42*60*60]/6048 kmph..
  then d=35kmph
• 8 years agoHelpfull: Yes(0) No(0)