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Determine the distance between x-intercept and 2-intercept of the plane where equation is 6x+8y-32=72.

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6x+8y-3z=72
intercept form x/(72/6)+y/(72/8)+z/(-72/3)=1

x intercept= 12
z intercept= -24
distance =sqrt(12^2+(-24)^2)
=sqrt(144+576)
=26.83
13 years agoHelpfull: Yes(19) No(1)

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