After 6 years Raju's fathers age will twice of the Raju's age 2 years ago. His mothers age was twice that of Raju age. Sum of the age of their parents.

• ANS: Sum of the age of raju's parents is(10 less than (4times of his age))=(4*r)-10
  
  Let Raju's father age=F
  Raju's mother age=M
  Raju's age=R
  f+6=2*(r-2) =>f+6=(2*r)-4
  m=2*r
  add both equations
  (f+6)+(m)=((2*r)-4)+(2*r)
  f+m+6=(4*r)-4
  f+m=(4*r)-10
• 11 years agoHelpfull: Yes(10) No(6)
• Let Raju's father age=F
  Raju's mother age=M
  Raju's age=R
  
  F+6=2(R+6)
  F= 2R+6
  M-2=2(R-2)
  M= 2R-2
  Therefore the sum of Raju’s Parent’s age is
  F+M=2R+6+2R-2
  F+M=4R+4
  I.e., 4 more than four rimes Raju’s age
• 11 years agoHelpfull: Yes(9) No(26)
• sol is 4R-2 where R is age of Raju
• 11 years agoHelpfull: Yes(2) No(4)
• let father's current age =F
  mother's current age= M
  raju's current age= R
  F+6=2(R+4)
  F=2R+2
  M=2R
  therefore
  F+M= 2R+2R+2
  F+M=4R
• 11 years agoHelpfull: Yes(2) No(4)
• @ROHIT KUMAR : plz explain why F+6=2(R+6)?? its shud be F+6=2(R-2) ??
• 11 years agoHelpfull: Yes(2) No(2)
• let fathers age be y,raju's be x and mother's be z...
  (y+6)=2(x+6)
  2x-y=-6...(1)
  z-2=2x-4
  2x-z=2...(2)
  therefore
  z+y=8
  ans=8.
  
  
• 11 years agoHelpfull: Yes(0) No(10)
• (4*r)-12, where r is the age of the raju
• 11 years agoHelpfull: Yes(0) No(0)
• ans: 4r
  let age of raju is r
  let age of fater be f
  let age of mother be m
  
  father's age after six years
  (f+6)=2(r-2)
  
  mother's age before two years(take it as two as its not specified)
  m-2=2(r-2)
  
  so 2(r-2)+2(r-2)=4r
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
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• 11 years agoHelpfull: Yes(0) No(0)
• F+6=2(R-2)-eq1
  M=2R
  
  M+F=2R+2+2R
  
  M+F=4R+2
• 11 years agoHelpfull: Yes(0) No(0)
• F+6=2(R+6)
  F= 2R+6
  M-2=2(R-2)
  M= 2R-2
  Therefore the sum of Raju’s Parent’s age is
  F+M=2R+6+2R-2
  F+M=4R+4
  4 more than four times Raju’s age
• 6 years agoHelpfull: Yes(0) No(0)