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If a pipe can fill the tank within 6 hrs. But due to leak it takes 30 min more. Now the tank is full then how much time will it take to empty the tank through the leak.?

Read Solution (Total 5)

Let the time taken by the leakage to empty the tank be X
Now
In 1hr it will fill 1/6th tank
And leakage will empty 1/X tank

Thus we can say that
1/6 - 1/X= 1/6.5
hence the value of X is 78hrs
11 years agoHelpfull: Yes(14) No(0)

78 hrs
xy/y-x

x = 6 hrs = 360 min
y = 6.30 hrs = 390 min

360*390/390-360
= 468 min = 468/60 = 78 hrs
11 years agoHelpfull: Yes(7) No(0)
Pipe takes 6 hrs to fill the thank= 6
due to leak it took 1/2 hr more = 6 and half=13/2

Work done by pipe to fill in 1 hr= 1/6
work done by leak in 1 hr = 2/13

Hence work done by leak in 1 hr = (1/6)-(2/13) =1/78
Hence it will take 78 hrs to completely empty the tank.
11 years agoHelpfull: Yes(7) No(0)
78 hrs i guess
11 years agoHelpfull: Yes(4) No(0)
78 hrs..
rate 2/13-1/6=1/78
hence.. 78 hrs
11 years agoHelpfull: Yes(1) No(0)

TCS Other Question

What is the sum of 28 terms in the following expressions :
(3^k)*(28Ck),
where (28Ck) is the number of ways of choosing k items from 28 items?
a) 2^56
b) 3*(2^27)
c) 3^29
d) 3*(4^27) What is k=0 to 28 k^2 (28Ck), where 28Ck is the number of ways of choosing k items from 28 items?
a) 406*2^27
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