For real number x, int(x) denotes integer part of x.int(x) is the largest integer less than or equal to x.int(1,2)=1,int(-2,4)=-3.
Find the value of int(1/2)+int(1/2+100)+int(1/2+2/100)+....+int(1/2+99/100)

• i too dont know how to solve but in 17th page i found the same que
  ANS:
  int(1/2)=0
  int(1/2+100)=100
  int(1/2+2/100)=0
  int(1/2+3/100)=0
  .....
  int(1/2+50/100)=int(100/100)=1
  .......
  int(1/2+99/100)=int(1.49)=1
  by adding all those values
  we will get 150
  in this the they have taken integers i.e rounded values
  
• 11 years agoHelpfull: Yes(20) No(2)
• sandy! how u added all the values...100+1+1=102
  150? how?
• 11 years agoHelpfull: Yes(2) No(0)
• @ ADITYA
  int(1/2+100)=100
  AFTER THIS
  FROM int(1/2+2/100) UPTO int(1/2+49/100) ARE ROUNDED AS 0
  FROM int(1/2+50/100)UPTO int(1/2+99/100) ARE ROUNDED AS 1 SO 100[int(1/2+100)]+50[FROM int(1/2+50/100)UPTO int(1/2+99/100)]=150
  *!!!HERE SUM LESS THAN 1(i.e,0.99,0.98.......0.1) ARE ROUNDED 0
  SIMILARLY SUM FORM 1 TO 1.99 ARE ROUNDED TO 1
  
• 11 years agoHelpfull: Yes(2) No(0)
• @ SANDHYA
  int is nothing but integer
  we know that 1/2=0.5
  but here SUM BETWEEN 0 AND 0.99 IS TAKEN AS 0
  AND SUM BETWEEN 1 TO 1.99 IS TAKEN AS 1
• 11 years agoHelpfull: Yes(2) No(0)
• very good sandy...............
  
• 11 years agoHelpfull: Yes(1) No(0)
• answer is 150.
• 11 years agoHelpfull: Yes(0) No(0)
• can u xpln me...further @durgesh plsssssssss
  
• 11 years agoHelpfull: Yes(0) No(1)