Ramesh and Neelesh start walking to meet one another from places 25 kms apart. If Ramesh walks at the rate of 2 kms an hour and Neelesh at 3 kms an hour, how many hours will it be before they meet?

• velocity of ramesh =2km/h
  velocity of neelesh =3km/h
  both start moving from both the end of 25km
  let at time t they meet
  let ramesh walks x km
  than neelesh have walk =25-x km
  2=x/t.......(a)
  3=25-x/t.....(b)
  on solving
  t=5 hr.
  
• 11 years agoHelpfull: Yes(11) No(0)
• yes 5 is the corrct ans as they started from opposite directions so their speed=3+2=5
  d=25km
  t=25/5=5 ans
• 11 years agoHelpfull: Yes(8) No(0)
• 1 hr 25 min
  as average speed=2*3*2/2+3
  and distance=25 km as they are 25 km apart
• 11 years agoHelpfull: Yes(3) No(6)
• See,as they started towards each other,so they are going in opposite directions,so relative speed is=2+3=5km/hr
  now total distance=25km.
  so tha answer will be=25/5=5hr
• 11 years agoHelpfull: Yes(3) No(0)
• 5 z correct
• 11 years agoHelpfull: Yes(1) No(1)
• distance travelled by both at same time should equal to 25
  2*t + 3*t =25
  t=5
• 11 years agoHelpfull: Yes(1) No(0)
• let they meet at d distance from ramesh and 25-d from neelesh
  then time taken to cover d distance should be equal to 25-d
  so as to meet.so let t be time.
  t=d/2
  t=25-d/3
  equate them d=10 and t=5.
• 11 years agoHelpfull: Yes(1) No(0)
• let they meet at x distance then,
  x/2=25-x/3, x=10km, t=10/2=15/3=5hrs
• 11 years agoHelpfull: Yes(1) No(1)
• (2 km/hr *5 hr) +( 3km/hr * 5hr)=25 kms
• 11 years agoHelpfull: Yes(0) No(0)
• Rel speed will be 3+2 = 5kms/hr.
  so 25/5 => 5hrs.
• 11 years agoHelpfull: Yes(0) No(0)
• their relative speed is 2+3=5km/hr
  total distance between them was 25km/hr
  so time taken=distance/r speed=25/5=5hr
• 11 years agoHelpfull: Yes(0) No(0)