The sum of three consecutive natural numbers each divisible by 3 is 72. What is the largest among them?
1. 25
2. 26
3. 27
4. 30 5. 26

• Let the three consecutive numbers be n-3, n, and n+3. So
  (n-3)+n+(n+3) = 72,
  3n = 72,
  n = 24.
  Thus the largest among them is n+3 = 27 (c).
• 9 years agoHelpfull: Yes(4) No(0)
• shorcut method:
  calculate average of given number
  3x=72
  x=72/3=24
  24 is not divisible by 3 so the number is 27.
  (or)
  these are consecutive numbers divisible by 3
  21+24+27 = 72
  largest num is 27.
  
  
• 9 years agoHelpfull: Yes(2) No(3)
• three consecutive numbers divisible by 3 3a,3a-3,3a+3
  3a+3a-3+3a+3=72
  9a=72
  a=8
  large number 3a+3=24+3=27
• 9 years agoHelpfull: Yes(0) No(1)
• let the 3 consecutive no.s be x,(x+3), (x+6)
  x+(x+3)+(x+6)=72,
  3x+9=72,
  3x=63
  x=21
  largest number among them = x+6=21+6=27
• 9 years agoHelpfull: Yes(0) No(1)
• 23+24+25=72 and among this three 25 is gratest.
• 8 years agoHelpfull: Yes(0) No(1)
• Generally people are confused that set of natural numbers are from 1 to 9 OR sometimes 0 to 9.But you should know that natural number are infinite started from 1..
  Assume our 1st natural odd numbr is 3. Therefore our next natural odd numbr which is also divisible by 3 will be 3+6=9 and next will be 3+12=15 and so on.
  According to this question, our equation will be: x+(x+6)+(x+12)=72
  3x+18=72
  Solving, we get x=18
  Hence our largest number becomes x+12=30.
• 7 years agoHelpfull: Yes(0) No(3)
• Let the first number be x
  
  Other numbers be (x + 6) and (x + 12)
  
  According to the question
  
  x + (x + 6) + (x + 12) = 81
  
  3x = 63
  
  x = 21
  
  Largest part = 21+ 12 = 33
• 4 years agoHelpfull: Yes(0) No(0)