if the difference of two number is 9 and product of two number is 10, what is the square of the sum of numbers

• let two numbers be a,b
  a-b=9,ab=10
  (a-b)^2=a^2+b^2-2ab
  a^2+b^2=81+20
  101
  (a+b)^2=101+2ab
  101+20=121
  so 121 is ths required ans
  
• 13 years agoHelpfull: Yes(7) No(0)
• x-y=9.......xy=10
  (x-y)^2=x^2+y^2-2xy
  so x^2+y^2=9^2+2*10=101
• 13 years agoHelpfull: Yes(1) No(3)
• let the 2 nos. be x & y
  x-y=9,xy=10;
  => (x+y)^2=(x-y)^2+4(x.y)
  => (x+y)^2=9^2+4.10
  =81+40
  =121
• 12 years agoHelpfull: Yes(0) No(0)