There is a circular pizza with negligible thickness that is cut into 'x' pieces by 4 straight line cuts. What is the maximum and minimum value of 'x' respectively?
a) 12,6
b) 11,6
c) 12,5
d) 11,5

• 12,5
  bcz 2 crosses and 2 horizontal for maximum. and 4 vertical or horizontal for minimum.
• 13 years agoHelpfull: Yes(8) No(6)
• dheeraj acording to u iam getting only 10 parts max
  
• 13 years agoHelpfull: Yes(5) No(1)
• plz post the right ans is urgent
• 13 years agoHelpfull: Yes(3) No(1)
• VEREFY OPTIONS FOUR LINS 4*4=16
  MAX=11,MIN=5
• 13 years agoHelpfull: Yes(2) No(8)
• thiz website is excellent but plz tell wheter this will appear in tcs or not becoz iam having tcs drive shortly its urgent reply
• 13 years agoHelpfull: Yes(1) No(1)
• max 11 and min 6
  
  
• 13 years agoHelpfull: Yes(1) No(3)
• ans is 11,5
• 13 years agoHelpfull: Yes(1) No(2)
• ans :: c)12,5
  cut 1 horizontal, 1 vertical and 2 crosses make maximum 12 pieces....
  and simply cut 4 horizontal or vertical make 5 minmum pieces.
  
• 12 years agoHelpfull: Yes(1) No(0)
• 12, 5
  For min cuts:
  We cut the pizza into half (1 cut, 2 pieces)
  We cut each half separately into halves (3 cuts, 4 pieces)
  We cut one of the quarters. (4 cuts, 5 pieces)
  
  For max cuts:
  We make three cuts diametrically to make 6 sector pieces.
  Then we keep each of the pieces over one another and cut all of them simultaneously, (the thickness is negligible) , so we get 12 pieces
• 10 years agoHelpfull: Yes(1) No(0)
• Minimum 5
  by cutting vertically or horizontal 4 time
• 13 years agoHelpfull: Yes(0) No(4)
• Let 'n' be no of straight cuts
  1. Min no of pieces = ( n + 1 )
  2. Max no. Of pieces = ( 1 + 2 + ....+ n ) + 1
• 3 years agoHelpfull: Yes(0) No(0)