George while driving along the highway saw road markers which are at equal distances from each other. He crosses the markers every 20 seconds. If he increases his speed by x meters per second, he crosses the markers at every 15 seconds. But if he increases his speed by y meters per second, he crosses the marker at every 10th second. If y-x = 40 meters per second, then what is the distance between two markers.

• s=d/20
  x=d/15-s
  y=d/10-s
  d/10-d/15=40
  d=1200
• 10 years agoHelpfull: Yes(38) No(5)
• 1200......
  let speed=z m/s
  distance=20z
  (z+x)15=20z
  (z+y)10=20z
  solve u will get 20z=1200
• 10 years agoHelpfull: Yes(14) No(7)
• let distance btw 2 marker = d
  15=d/x , d=15x
  10=d/y d=10y
  equating d
  15x=10y
  15x-10y=0
  y-x=40
  solving two eqn
  x=80
  hence d= 15*80
  = 1200
  
• 8 years agoHelpfull: Yes(3) No(0)
• for speed x,t=15s
  for speed y,t=10sec
  given:-y-x=40
  on solving we get
  y=120 & x=80m/s
  d=s*t
  =120*10
  1200m
• 10 years agoHelpfull: Yes(2) No(7)
• Speed1=x/15
  
  speed2=x/10
  
  as, s2-s1=40 m
  (x/15 ) - (x/10)= 40
  
  thus, x=1200 m
• 8 years agoHelpfull: Yes(2) No(0)
• 1200...we will get 3 eq...solving them will give the ans
• 10 years agoHelpfull: Yes(0) No(14)