TWO STATIONS A & B ARE 110 KM APART. ONE TRAIN STARTS FROM A AT 7 AM, AND TRAVELS TOWARDS B AT 20KMPH. ANOTHER TRAIN STARTS FROM B AT 8 AM AND TRAVELS TOWARDS A AT 25KMPH. AT WHAT TIME WILL THEY MEET?
A. 9 AM
B. 10 AM
C. 11 AM
D. 10.30 AM

• let T=xhrs
  A-->Distance=20xKm
  B-->Distance=25(x-1)km[because diff(7,8) is 1]
  20x+25(x-1)=110km then x=3hr
  so 7am+3hr=10am.
• 13 years agoHelpfull: Yes(20) No(1)
• since A covers 20km in 1hr when B starts with A at 8 AM in opposite direction,
  relative speed=25+20=45kmph
  time to meet=90/45=2hr
  8+2=10AM
• 13 years agoHelpfull: Yes(14) No(0)
• at 10 AM
  BECAUSE AT A TRAIN1 STARTS AT 7 AM AND AT B TRAIN2 STARTS AT 8AM AT 8 AM TRAIN1 ALREADY 20 KM PASSED AWAY FROM A AND TRAIN 1 AND TRAIN2 MOVING OPPOSITE DIRECTIONS THEIR SPEED 20+25=45
  THEY TAKEN TIME 2 HOURS AND THEY MEET AT 10 AM
  
• 8 years agoHelpfull: Yes(0) No(1)
• b 110-20/45
  
• 8 years agoHelpfull: Yes(0) No(0)