26. In a single throw with two dice, find the probability that their sum is a multiple either of 3 or 4.
option
a) 1/3
b) 1/2
c) 5/9
d)17/36

• 5/9
  20 cases which lead sum divisible either by 3 or 4 and total no. of cases is 36
  
• 11 years agoHelpfull: Yes(43) No(1)
• these are the possible solution sets
  (1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3) (1,3)(2,2)(2,6)(3,1)(3,5)(4,4)(5,3)(6,2)(6,6)
• 11 years agoHelpfull: Yes(27) No(2)
• their sum can be 3,4,6,8,9,12
  20 possible cases.so probability is (20/36)=(5/9)
• 11 years agoHelpfull: Yes(7) No(1)
• 5/9
  (1,2)(1,3)(1,5)(2,1)(2,2)(2,4)(2,6)(3,1)(3,3)(3,5)(3,6)(4,2)(4,4)(4,5)(5,1)(5,3)(5,4)(6,2)(6,3)(6,6)
• 11 years agoHelpfull: Yes(7) No(0)
• 18 cases will lead sum divisible by 3 or 4 out of 36
  hence 1/2
• 11 years agoHelpfull: Yes(3) No(9)
• answer will be 5/9 since 20 cases are possible.
  and n(s) = 36
• 11 years agoHelpfull: Yes(3) No(0)
• 5/9
  20 cases
• 11 years agoHelpfull: Yes(3) No(0)
• i think the prob may be 17/36..
  mul of 3 are 12..
  mul of 4 are 9..
  in both common are 4...
  so 12/36+9/36-4/36=17/36
• 11 years agoHelpfull: Yes(3) No(9)
• (1,2),(2,1),(1,3),(3,1),(1,5),(5,1),(2,2),(2,4),(4,2),(2,6),(6,2),(3,3),(3,5),(5,3),(3,6),(6,3),(4,4),(6,6)
  
  Hence 18/36=1/2
• 11 years agoHelpfull: Yes(2) No(10)
• there are only 20 outcomes whose sum is multiple of 3 or 4 so probability is 5/9
• 11 years agoHelpfull: Yes(2) No(0)
• (1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3),(6,6)
  possible cases=12
  total cases=36
  probability=12/36=1/3
• 11 years agoHelpfull: Yes(1) No(10)
• 5/9
  20 cases
• 11 years agoHelpfull: Yes(1) No(0)
• (12+9-1)/36 = 5/9
  
• 11 years agoHelpfull: Yes(1) No(0)
• 1/2 will be the answer
• 11 years agoHelpfull: Yes(1) No(2)
• 5/9
  multiples of 3:12,multiples of 4:8;
  =>12+8/36=5/9
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• total favourable cases will be 20 out of 36 total possible cases therefore p(multiple of 3 or 4) = 5/9
• 11 years agoHelpfull: Yes(0) No(0)
• 18/36 so the answer is 1/2
• 11 years agoHelpfull: Yes(0) No(3)
• 5/9 becoz there are 20 favoural cases and 36 total cases to probality is 5/9
• 11 years agoHelpfull: Yes(0) No(0)