A manufacturer of chocolates makes 6 different flavours of chocolates. The chocolates are sold in boxes of 10. How many “different” boxes of chocolates can be made ?

• ANS 15C5 = 3003
  it is a case of special euations "x1+x2+...+x6 = s" where x1, x2,...,x6 >= 0.
  in such a case the formula for non negative integral solutions is (n+s-1)C(n-1).
  here n=6 & s=10. the answer is 15C5 = 3003
• 11 years agoHelpfull: Yes(25) No(3)
• 10^6 - as 6 chocolates must be placed in 10 boxes!!! r^n
• 11 years agoHelpfull: Yes(23) No(19)
• 6^10. since one choclate box could have any of the 6 choclates and there are 10 boxes. Hence 6*6*6*6*6*6*6*6*6*6 ways.
• 11 years agoHelpfull: Yes(16) No(10)
• is it this year question??
• 11 years agoHelpfull: Yes(3) No(5)
• sruthi cn be explain ans.........
• 11 years agoHelpfull: Yes(3) No(0)
• a+b+c+d+e+f=10
  hence ways is 10+6-1C6-1= 15C5
• 11 years agoHelpfull: Yes(1) No(2)
• Is it not 10^6.This sum is like letters and post boxes.
• 10 years agoHelpfull: Yes(1) No(1)
• 10c6..shld b crrct..
• 11 years agoHelpfull: Yes(0) No(22)
• stuti is rght..
  it wll b 6^10..coz evry chchlte can be choose in 6 way..so 10 chchltes can be choose in 6*6*6*6*6*6*6*6*6*6=6^10 way..
• 9 years agoHelpfull: Yes(0) No(0)