What is the 32nd word of "WAITING" in a dictionary?

• AGI.....4!= 24
  AGNIITW=25
  AGNIIWT=26
  AGNITIW=27
  AGNITWI=28
  AGNIWIT=29
  AGNIWTI=30
  AGNTIIW=31
  AGNTIWI=32....
• 10 years agoHelpfull: Yes(44) No(8)
• AGI----(4!)=24
  AGII---(3!)=6
  REST 2 WORD IN ALPHABATICAL ORDER WILL BE
  AGIINTW--31
  AGIINWT---32 So answer is AGIINWT...
• 10 years agoHelpfull: Yes(36) No(26)
• AGNTIWI- ans
• 10 years agoHelpfull: Yes(27) No(7)
• First arrange the words of waiting in Alphabetical Order
  i.e WAITING as
  A,G,I,I,N,T,W
  Start wid A_ _ _ _ _ _ ->This can be arranged in 6!/2! ways=720/2=360 ways
  so can't be arranged starting with A alone as it is asking for 32nd word so it is out of range
  
  
  Now if AG_ _ _ _ _->then remaining words can be arranged in 5!/2! ways so,120/2=60 ways again out of range as it has to be within 32 words.
  
  now, if AGI_ _ _ _-> now the words can be arrange in 4! ways =24 now can be arranged in 4!/2! ways or 12 ways
  
  so,24+12 =36th word so out of range..
  
  now AGNI_ _ _->can be arranged in 3! ways =6 ways
  so 24+6=30 within range..
  
  Now only two word left so,arrange in alphabetical order...
  AGNTIIW it is the 31st word so..
  the 32nd word is ....just interchange the position of last two letters
  i.e the word is..AGNTIWI....
  
• 10 years agoHelpfull: Yes(26) No(13)
• pls anybody can explain how to solve this problem?
• 10 years agoHelpfull: Yes(2) No(1)
• hey plz explain wats the ques is?????????
• 10 years agoHelpfull: Yes(2) No(3)
• the ans is AGNIITW
  
• 10 years agoHelpfull: Yes(2) No(2)
• AGI----=24 ways
  AGII---=6 ways
  AGINITW=1way sums upto 31 ways and 32 is reversing the last two letters ,
  AGINIWT=32
• 9 years agoHelpfull: Yes(2) No(2)
• AIGWITN -ans
• 10 years agoHelpfull: Yes(0) No(14)
• First arrange the words of waiting in Alphabetical Order
  i.e WAITING as
  
  A,G,I,I,N,T,W
  Start wid A_ _ _ _ _ _ -This can be arranged in 6!/2! ways=720/2=360
  
  
• 10 years agoHelpfull: Yes(0) No(10)
• I think it's AGNWTII
• 10 years agoHelpfull: Yes(0) No(7)
• plzzzz explain this problem.............
  
• 9 years agoHelpfull: Yes(0) No(0)
• 32nd word = AGIINWT
• 9 years agoHelpfull: Yes(0) No(1)
• AGI....4!=24
  AGII....3!=6
  
  31st word ll be AGINITW
  32nd Word ll be AGINIWT
• 9 years agoHelpfull: Yes(0) No(0)
• 2^74 + 2^2058 + 2^2n =(2^37)^2 + (2^1029)^2 + (2^n)^2
  now, if we put 2^37 = a ; 2^1029 = b; Then for the above expression to be perfect
  square 2^2n must be equal to (2*a*b)= 2*(2^37)*(2^1029);
  ==> 2^2n = 2^(1067)
  ==> 2n = 1067 ,
  but this case is not possible since R.H.S is an odd integer whereas L.H.S is an
  even integer.
  So , the above mentioned case can't hold.
  Now,if we put 2^37 = a; 2^n = b ; So, for the given expression to be perfect square
  2^2058 = (2*a*b)= 2*(2^37)*(2^n) = 2^(n+38);
  So, 2058 = (n+38)
  => n = 2020
  So,The answer is n = 2020
• 4 years agoHelpfull: Yes(0) No(1)
• AGNTIWI
  ANSWER
• 4 years agoHelpfull: Yes(0) No(1)