A man who goes to work long before sunrise every morning gets dressed in the dark. In his sock drawer he has 6 black and 8 blue socks. What is the probability that his first pick was a black sock, but his second pick was a blue sock?

(6c1/14c1)*(8c1*13c1)=24/91
10 years agoHelpfull: Yes(14) No(0)
@ DEVIKA.R
Given that there are 6 black and 8 blue soks out of them we have to pick up 2 socks
which 1 of them is black and the other is blue
blue sock can be pick up in 6c1 ways where as blue can be picked up in 8c1 ways
there are 14 socks in total.here replacement is not mentioned so
so probability 1st black sock can be 6c1/14c1
probability of 2nd blue sock is 8c1/(14-1)c1 (as out of 14 one black is picked already)
so total probability=6/14*8/13=24/91
10 years agoHelpfull: Yes(10) No(1)
(6c1*8c1)/14c2
=(6*8)/91
=48/91
10 years agoHelpfull: Yes(8) No(13)
(6/14)*(8/13)=24/91
10 years agoHelpfull: Yes(3) No(2)
HI SAURABH KESHARI, CAN U EXPLAIN
10 years agoHelpfull: Yes(2) No(1)
6*6/14*13 = 24/91
10 years agoHelpfull: Yes(2) No(3)
(6c1/14c1)*(8c1/13c1)=6/14*8/13=24/91
5 years agoHelpfull: Yes(0) No(0)

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